Lecture 18: Band Structures of Transition Metal Oxides
Wed 11/04/2026 · Meeting 20
ReO₃ and perovskite band structures and periodic trends
Reading: Woodward, Karen, Evans, and Vogt, Solid State Materials Chemistry Ch. 6
Learning Objectives: TM Oxide Band Structures
Band Structures of Transition Metal Oxides
Describe the crystal structureof ReO₃ and its relationship to perovskite structures
Construct band structure diagramsfrom molecular orbital diagrams for octahedral transition metal complexes
Identify and interpretoxygen 2p bands and metal d bands (π* and σ*) at special k-points
Extract key energetic parametersfrom band structures: octahedral ligand field splitting, charge transfer energy, and band gap
Predict periodic trendsin band structure when moving across the periodic table (changing electronegativity and covalency)
Analyze competing effectsof spatial overlap versus energetic overlap when moving down the periodic table (3d vs 4d vs 5d)
Electronic Band Structure
An octahedron's molecular orbital diagram becomes bands running through the special points of the zone. By the end of the lecture we can read this ReO3 band structure.
Per Solid State Materials Chemistry, §6.6.4, p.231.
Rhenium Trioxide
Substance
Conductivity (S/m)
Ag
62 × 106
Cu
59 × 106
Al
38 × 106
ReO3
11 × 106
Ti
2.5 × 106
Mn
0.62 × 106
Per Solid State Materials Chemistry, §10.1, p.396.
Perovskites
ReO3 — Re at the corners, O at every edge centre, the cage at the cell centre empty.
SrTiO3 — the same framework with a large Sr2+ filling that cage.
Treat the big cation as an electropositive electron donor — it bonds ionically and, in the limit, simply hands its electrons to the metal–oxide framework — and perovskites and ReO3 are isostructural, so their band structures are the same problem.
Per Solid State Materials Chemistry, §6.6.5, p.233.
First Brillouin Zone – Primitive Cubic
label
coordinates
Γ
0a* + 0b* + 0c*
X
(1/2)a* + 0b* + 0c*
M
(1/2)a* + (1/2)b* + 0c*
R
(1/2)a* + (1/2)b* + (1/2)c*
label
wave vector (Cartesian)
Γ
0kx + 0ky + 0kz
X
(π/a)kx + 0ky + 0kz
M
(π/a)kx + (π/a)ky + 0kz
R
(π/a)kx + (π/a)ky + (π/a)kz
The zone boundary lies at half of each reciprocal lattice vector, where $k = \pi/a$.
Per Solid State Materials Chemistry, §6.4.2, p.219.
MO Diagram for the ReO₆⁶⁻ Octahedron
O 2p SALCs18 of them — six oxygens × three 2p orbitals — splitting into six σ and twelve π combinations
Re valence orbitalsfive 5d, split by the octahedral field into t2g and eg, plus the higher 6s and 6p
Near the Fermi levelonly the nonbonding O 2p and the antibonding Re 5d states matter; the 2s orbitals are too deep to mix
Per Solid State Materials Chemistry, §6.6.4, p.231.
How Many Bands Are There?
orbitals in the unit cell
bands
1 Rhenium × 1 (6s orbitals)
1
1 Rhenium × 3 (6p orbitals)
3
1 Rhenium × 5 (5d orbitals)
5
3 Oxygen × 3 (2p orbitals)
9
3 Oxygen × 1 (2s orbitals)
3
Per Solid State Materials Chemistry, §6.6.4, p.231.
Band Structure of ReO₃
O 2p bandsnine bands (three oxygens × three 2p), all full: the eighteen oxygen electrons fill every one
Re t2g (π*) bandsthree bands, and Re6+ is 5d¹, so they are one-sixth filled — the Fermi level lies inside them
Re eg (σ*) bandstwo bands, empty, and pushed highest because σ antibonding beats π antibonding
Per Solid State Materials Chemistry, §6.6.4, p.231.
Orbital Overlap: Re 5d $e_g$ $\sigma^*$ Bands
At Γno O 2p can mix; only O 2s reaches dx²-y², so weakly antibonding
At MO 2p overlaps it σ*, and the band climbs: strongly antibonding
Per Solid State Materials Chemistry, §6.6.4, p.231.
Orbital Overlap: Re 5d $t_{2g}$ $\pi^*$ Bands
At Γdxy matches no O 2p or 2s by symmetry: pure Re 5d, nonbonding, all three degenerate
At Mπ overlap with O 2p switches on and the band rises: antibonding
Per Solid State Materials Chemistry, §6.6.4, p.231.
Orbital Overlap: O 2p Nonbonding Bands
The circled band is the top of the O 2p block, the states that stay mostly nonbonding.
At Γneither bonding nor antibonding between oxygens, and no Re s, p or d orbital has the symmetry to overlap
At Mthe phases flip along x and y but nothing changes; a very weak π overlap with Re 6p bends the band slightly
Per Solid State Materials Chemistry, §6.6.4, p.231.
Reading $\Delta$, CT and $E_\text{g}$ off the Bands
The generic d⁰ AMO3 perovskite, so the brackets read M d; ReO3's own values come on the next slide.
Δ at Rt2g and eg are both fully antibonding at R, so their splitting is the octahedral ligand field splitting
CT at ΓO 2p and M d are both nonbonding at Γ, so the gap is the energy to move an electron from O 2p onto the metal: the charge transfer energy
Eg, R to Γhighest O 2p state to lowest M d state: in a d⁰ compound the R-to-Γ energy is the band gap, and it is indirect
Per Solid State Materials Chemistry, §6.6.5, p.233.
*All parameters calculated except M–O distance and band gap, which are experimental values.
Moving left-to-right (Hf → Re) the effective nuclear charge increases
Metal-oxygen bond distancedecreases
Bandwidthincreases (more energetic and spatial overlap)
Δincreases
Charge transfer energydecreases
Band gapdecreases
Per Solid State Materials Chemistry, §6.6.5, p.233.
Periodic Trends: Down a Group
SrTiO3
BaHfO3
M–O distance (Å)*
1.95
2.09
e− configuration
3d0
5d0
σ* bandwidth (eV)
4.1
5.1
π* bandwidth (eV)
2.4
3.5
Δ (eV)
3.9
5.5
CT (eV)
4.1
5.3
Band gap (eV)*
3.1
5.5
*All parameters calculated except M–O distance and band gap, which are experimental values.
Moving down a column (Ti → Hf)
Metal-oxygen bond distanceincreases
Bandwidthincreases (more spatial overlap)
Δincreases (more spatial overlap)
Charge transferincreases
Band gapincreases
Per Solid State Materials Chemistry, §6.6.5, p.233.
Check Your Understanding: Counting Bands
3. The unit cell of ReO₃ contains one Rhenium and three Oxygen atoms. How many bands are expected to arise from the Oxygen 2p orbitals?
A.6 bands
B.9 bands
C.3 bands
D.5 bands
Answer: B. 9 bands
There are three oxygen atoms, and each has three p-orbitals (px, py, pz), leading to 3 × 3 = 9 bands.
Check Your Understanding: $t_{2g}$ Character at Γ
5. At the Gamma (Γ) point (k = 0,0,0) of the Brillouin zone, what is the bonding character of the Rhenium 5d t2g (dxy, dxz, dyz) orbitals?
A.Strongly sigma anti-bonding (σ*) with Oxygen 2p
B.Weakly anti-bonding with Oxygen 2s
C.Strongly pi anti-bonding (π*) with Oxygen 2p
D.Non-bonding, due to symmetry constraints with Oxygen 2p and 2s orbitals.
Answer: D. Non-bonding, due to symmetry constraints with Oxygen 2p and 2s orbitals.
The lecture explicitly states that at Gamma, the t2g orbitals ‘cannot overlap at all’ with the oxygen orbitals, making them purely non-bonding.
Check Your Understanding: The $\sigma^*$ Band from Γ to M
6. Why does the energy of the σ* (eg, dx²-y²) band increase significantly when moving from the Gamma (Γ) point to the M point?
A.At M, the crystal field splitting energy (Δo) disappears, causing the band to rise.
B.The orbital becomes non-bonding at M.
C.At M, it hybridizes with the Rhenium 6s orbital, pushing it up in energy.
D.At M, it gains strong σ* anti-bonding character from interacting with Oxygen 2p orbitals.
Answer: D. At M, it gains strong σ* anti-bonding character from interacting with Oxygen 2p orbitals.
At Gamma, it can't mix with O 2p, but at M, symmetry allows strong σ* interaction with the O 2p orbitals (which have good energy overlap), raising the energy.
Practice questions
Work the Lecture 18 practice questions before the next class.